The settling velocity of a spherical particle of diameter less than 0.1 mm as per Stock’s law, is__________________?

A. Vs = 418 (Gs – Gw) d [(3T + 70)/100]

B. Vs = 418 (Gs – Gw)d² [(3T + 70)/100]Correct Answer

C. Vs = 218 (Gs – Gw)d² [(3T + 70)/100]

D. Vs = 218 (Gs – Gw)d [(3T + 70)/100]

Correct Option: B. Vs = 418 (Gs – Gw)d² [(3T + 70)/100]

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